Re: lines as array elements

[stephen.talley@xxxxxxxxxxxxxxx (Steve Talley)]

Try:


#!/bin/zsh
 
IFS="
"
 
i=1;
for line in `cat file`
do
    x[$i]=$line
    i=`expr $i + 1`
done


Steve

> From zsh-users-request@xxxxxxxxxxxxxxxxxxxxxxxx Fri Jun 27 16:53 MDT 1997
> From: unpingco@xxxxxxxxxxxx (Jose Unpingco)
> Subject: lines as array elements
> To: zsh-users@xxxxxxxxxxxxxxx (zsh)
> Date: Fri, 27 Jun 1997 15:38:18 -0700 (PDT)
> 
> hi,
> 
> I have  a file that looks like this:
> 
>     -503  306 -498  428
>     -500  435 -501  588
>     -497  440 -501  593
>     -505  451 -502  601
>     -510  324 -511  454
>     -505  328 -511  459
>     -506  333 -509  464
>     -520  342 -492  463
> 
> what I'd like to do is get each line into an array element like
> 
> x[1]="-503  306 -498  428"
> 
> up to
> 
> x[8]="-520  342 -492  463"
> 
> I've tried x=(`cat file`) but that splits on the spaces between the
> numbers. I've looked at the IFS variable and tried to change it to
> newline but that doesn't work as expected.
> 
> Thanks. 
> 
> -- 
> Thank you for your time and consideration.  
> 
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> Jose Unpingco                                Mail Code ECE 0407
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