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Re: Notes on bash(1)
- X-seq: zsh-users 1973
- From: "Michael Barnes" <mibarnes@xxxxxx>
- To: zsh-users@xxxxxxxxxxxxxxx
- Subject: Re: Notes on bash(1)
- Date: Wed, 9 Dec 1998 11:38:59 -0500
- In-reply-to: <199812091619.LAA15213@xxxxxxxxxxxxxxxxxxxx>; from Jason Price on Wed, Dec 09, 1998 at 11:19:27AM -0500
- Mail-followup-to: zsh-users@xxxxxxxxxxxxxxx
- References: <199812091619.LAA15213@xxxxxxxxxxxxxxxxxxxx>
On Wed, Dec 09, 1998 at 11:19:27AM -0500, Jason Price wrote:
> >From zsh-workers:
>
> (Quoting got screwed up... Sorry...)
>
> Forwarded message:
> > > * ${parameter/pattern/string} and ${parameter//pattern/string}
> > > pattern is expanded as per pathname expansion. [munch]
> >
> > [munch]
> > Maybe it can be done quite simply by upgrading the extra flags Sven
> > added for # and % to match internal bits of a parameter's value.
>
> there are a heck of a lot of ${...} modifiers that are wonderfully useful,
> but in my searching through the man pages, I havn't found an equivelent to
> basename /usr/local/bin/mumble -> mumble. I need to pull the basename out
> of path strings quite offten, and I'd like to do so in shell.
>
> Is this ... (wait, this is zsh) How can I do this?
~squid/logs foo=/usr/local/bin/mumble
~squid/logs echo $foo[(ws:/:)-1]
mumble
~squid/logs foo=/usr/local/bin/mumble/
~squid/logs echo $foo[(ws:/:)-1]
mumble
This makes foo an array with the word separator `/' and gives the last
element in that array.
I am sure there are otherways to do this but this works for me.
Mike
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