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RE: huh? where did the . come from in my $PATH????

X-seq: zsh-users 2304
From: "Andrej Borsenkow" <borsenkow.msk@xxxxxx>
To: "TjL" <tjlists@xxxxxxxxxxx>, "Zsh Users" <zsh-users@xxxxxxxxxxxxxx>
Subject: RE: huh? where did the . come from in my $PATH????
Date: Wed, 14 Apr 1999 17:38:48 +0400
Importance: Normal
In-reply-to: <9904140918410.2711-100000@localhost>
Mailing-list: contact zsh-users-help@xxxxxxxxxxxxxx; run by ezmlm

>          if [ -d "$i" ]; then
>             PATH=$i:$PATH

>
> Which works niftily, except that at the end of the $PATH is "." !!
>

The very first time PATH is obviously empty and expands to nothing, so you
get
    PATH=$i:

empty PATH component is the same as . (current dir).

Use array `path' instead of scalar PATH:

   path=($i $path)

Or explicitly test if PATH is not empty

  if [[ -n "$PATH" ]]; then
    PATH=$i:$PATH
  else
    PATH=$i
  fi

/andrej

References:
- huh? where did the . come from in my $PATH????
  - From: TjL

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