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Re: Completion once again..
- X-seq: zsh-users 3590
- From: Sven Wischnowsky <wischnow@xxxxxxxxxxxxxxxxxxxxxxx>
- To: zsh-users@xxxxxxxxxxxxxx
- Subject: Re: Completion once again..
- Date: Mon, 22 Jan 2001 13:17:20 +0100 (MET)
- In-reply-to: Tarmo Järvi's message of Sat, 20 Jan 2001 16:26:42 +0000 (GMT+00:00)
- Mailing-list: contact zsh-users-help@xxxxxxxxxx; run by ezmlm
Tarmo Järvi wrote:
> Hello list,
>
> and my apologies if this question has been asked several times but I couldn't find answer anywhere.
>
> Anyway, here's my question: I have in ~/.zshrc:
>
> compctl -g '*.(tar|t[ag]z|tz|tar.gz|tar.Z|tarZ|tar.bz2)' + -g '*(-/)' {,ls,un,g,gnu}tar
>
> and in /tmp:
>
> foo.tar
> bar/
> bar/snafu.tar
>
> if I 'cd /tmp' and type tar <TAB> I get:
>
> tar foo.tar
>
> How do I get menu with all directories files matching definitions above? I've tried numerous tricks but I couldn't made it.
If you only want to see the matching files together with the
directories, use only one `-g' and apend the `*(-/)' to the `*.(tar|...)'
with a space betwen them.
If you want to see `foo.tar' and `bar/snafu.tar' as completions at the
same time, you would have to write a completion function and make it
be called `compctl -K'. There you could use `**/*.(tar|...)'. But I
doubt that you really want that, because of the possibility of
accidentally making it scan great parts of your directory structure.
Or maybe I didn't really understand what you want?
Bye
Sven
--
Sven Wischnowsky wischnow@xxxxxxxxxxxxxxxxxxxxxxx
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