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Re: how to search for a substring in a parameter?
- X-seq: zsh-users 5692
- From: Peter Stephenson <pws@xxxxxxx>
- To: zsh-users@xxxxxxxxxx
- Subject: Re: how to search for a substring in a parameter?
- Date: Mon, 13 Jan 2003 18:32:58 +0000
- In-reply-to: "Carlos Carvalho"'s message of "Mon, 13 Jan 2003 16:13:04 -0200." <15907.432.363150.443412@xxxxxxxxxxxxxx>
- Mailing-list: contact zsh-users-help@xxxxxxxxxx; run by ezmlm
Carlos Carvalho wrote:
> I'm trying to see if the value of a parameter contains a given string
> but didn't find an elegant way.
What was wrong with
if [[ $foo = *pattern* ]]; then
...
? The patterns are identical to those in parameter substitution.
> All pattern matching substitutions
> return only the non-matched portion of the value.
You can use the flags M for the matched portion combined with either
head or tail matching using the S flag to tell it to match substrings,
i.e. anywhere in the pattern.
% foo='this is a pattern, too'
% print ${(MS)foo##pattern}
pattern
The M flag doesn't work with the `/' or `//' substitutions (and the S
flag is differnt --- it forces the shortest match). Not clear
if that's `really' a bug, but it does agree with the documentation.
--
Peter Stephenson <pws@xxxxxxx> Software Engineer
CSR Ltd., Science Park, Milton Road,
Cambridge, CB4 0WH, UK Tel: +44 (0)1223 692070
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