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Re: how to force scalar to be an array?

X-seq: zsh-users 7941
From: Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx>
To: ZSH User List <zsh-users@xxxxxxxxxx>
Subject: Re: how to force scalar to be an array?
Date: Fri, 27 Aug 2004 14:27:36 -0700 (PDT)
In-reply-to: <20040827154905.GA26846@xxxxxxxxx>
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References: <20040827154905.GA26846@xxxxxxxxx>
Reply-to: zsh-users@xxxxxxxxxx

I'm sorry, I missed the second (result="foo") assignment when I was trying 
the examples, so I thought you always had a multi-word scalar to start 
with.  Ignore my previous message.

A scalar is a scalar, and the result of splitting a scalar is only an 
array if the split actually does something.

Further, using $=array forces the array to be a scalar and then applies
the preceding rule.

So your only safe bet is to actually assign the scalar to an array, and
then use subscripting on the array.

Follow-Ups:
- Re: how to force scalar to be an array?
  - From: Andy Spiegl

References:
- how to force scalar to be an array?
  - From: Andy Spiegl

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