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Re: renameing numbered files
- X-seq: zsh-users 10434
- From: Meino Christian Cramer <Meino.Cramer@xxxxxx>
- To: zsh-users@xxxxxxxxxx
- Subject: Re: renameing numbered files
- Date: Sun, 25 Jun 2006 07:12:47 +0200 (CEST)
- In-reply-to: <060624215422.ZM7997@xxxxxxxxxxxxxxxxxxxxxx>
- Mailing-list: contact zsh-users-help@xxxxxxxxxx; run by ezmlm
- References: <20060625.052545.74742529.Meino.Cramer@xxxxxx> <060624215422.ZM7997@xxxxxxxxxxxxxxxxxxxxxx>
From: Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx>
Subject: Re: renameing numbered files
Date: Sat, 24 Jun 2006 21:54:22 -0700
> On Jun 25, 5:25am, Meino Christian Cramer wrote:
> }
> } How can I do this in a most zshy way?
>
> autoload -U zmv
> zmv -Qf 'Example(<->).txt(On)' 'Example${(l:4::0:)$(($1+10))}.txt'
>
> That probably deserves some explanation:
Yes, of course! Magic always deserves some explanations !
:o) :o) :o):o):o) :o) :o) :o) :o):o) :o) :o) :o) :o) :o)
> Either the -Q option or (#qOn) is required because zmv turns off "bare"
> glob qualifiers by default.
>
> The -f option is required because the set of source names overlaps with
> the set of destination names (0102 is in both).
>
> Sorting (On) forces the higher-numbered files to be renamed first,
> otherwise 0092 --> 0102 --> 0112 will result (the original 0102 would
> be lost). If the leading zeroes weren't there, you'd need (nOn) for
> numeric sorting.
>
> Using $(($1+10)) discards leading zeroes, so (l:4::0:) puts them back.
>
> I suggest playing around with "zmv -n" a bit to be sure it's going to
> do what you intended.
>
Thanks a lot Bart!
I will experiment with that...
Have a nice weekend!
mcc
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