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Re: /usr/bin/printf
- X-seq: zsh-users 13833
- From: Nikolai Weibull <now@xxxxxxxx>
- To: Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx>
- Subject: Re: /usr/bin/printf
- Date: Fri, 13 Feb 2009 04:40:20 +0100
- Cc: zsh-users@xxxxxxxxxx
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On Fri, Feb 13, 2009 at 04:25, Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx> wrote:
> The problem is that $1 is first expanded by the command parser and then
> passed to "print".
> The (q) tells zsh to insert a backslash before any special characters
> that appear in the value of $1, including the backslash in "\n". Then
> "print" strips the extra backslashes off again and the final output is
> the original string.
Couldn't one use the -r switch to print as well?
Also, it seems that you would more or less always want to make sure to
do this whenever printing anything.
I think it's really unfortunate that print has the same default
interpretation of its arguments as echo. It would have been nice if
there was a command that didn't interpret escapes by default.
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