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Re: simple substitution?

X-seq: zsh-users 14300
From: Frank Terbeck <ft@xxxxxxxxxxxxxxxxxxx>
To: zsh-users@xxxxxxxxxx
Subject: Re: simple substitution?
Date: Wed, 12 Aug 2009 13:57:02 +0200
In-reply-to: <20090812133916.6ab5adcf.tartifola@xxxxxxxxx>
Mail-followup-to: zsh-users@xxxxxxxxxx
Mailing-list: contact zsh-users-help@xxxxxxxxxx; run by ezmlm
References: <20090812133916.6ab5adcf.tartifola@xxxxxxxxx>

tartifola@xxxxxxxxx <tartifola@xxxxxxxxx>:
> I'm trying to understand expansion end substitution and I'm lost in
> what should be a simple substitution. Here my example
> 
> >foo=4
> >echo ${foo}
> 4
> >FO=fo
> >O=o
> >echo \${${FO}${O}}
> ${foo}
> 
> while I was expecting '4'. What am I missing?

What would make you think that in the first place?
You can get that effect by doing:

[snip]
foo=4
FO=fo
O=o
print ${(P)${:-$FO$O}}
[snap]

Details can be found in 'man zshexpn'.

Regards, Frank

References:
- simple substitution?
  - From: tartifola

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