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Re: Assign to parameter in parameter -- opposite of ${(P)name}?

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From: Frank Terbeck <ft@xxxxxxxxxxxxxxxxxxx>
To: "Benjamin R. Haskell" <zsh@xxxxxxxxxx>
Subject: Re: Assign to parameter in parameter -- opposite of ${(P)name}?
Date: Sat, 10 Jul 2010 03:13:47 +0200
Cc: Zsh Users <zsh-users@xxxxxxx>
In-reply-to: <alpine.LNX.2.01.1007091908420.4808@xxxxxxxxxxx> (Benjamin R. Haskell's message of "Fri, 9 Jul 2010 19:17:38 -0400 (EDT)")
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Benjamin R. Haskell wrote:
> It's the end of the week, and I'm tired, so I'm sure I'm completely 
> overlooking something obvious, but how do you *assign* to a parameter 
> whose name is in a parameter?
[...]
> Do I need to resort to 'eval'?

% typeset foobar=baz
% print ${foobar}
baz

Regards, Frank

-- 
In protocol design, perfection has been reached not when there is
nothing left to add, but when there is nothing left to take away.
                                                  -- RFC 1925

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- Assign to parameter in parameter -- opposite of ${(P)name}?
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