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Re: Assign to parameter in parameter -- opposite of ${(P)name}?

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From: Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx>
To: "Benjamin R. Haskell" <zsh@xxxxxxxxxx>
Subject: Re: Assign to parameter in parameter -- opposite of ${(P)name}?
Date: Sat, 10 Jul 2010 10:39:37 -0700
Cc: Zsh Users <zsh-users@xxxxxxx>
In-reply-to: <alpine.LNX.2.01.1007091908420.4808@xxxxxxxxxxx>
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On Fri, Jul 9, 2010 at 4:17 PM, Benjamin R. Haskell <zsh@xxxxxxxxxx> wrote:
> It's the end of the week, and I'm tired, so I'm sure I'm completely
> overlooking something obvious, but how do you *assign* to a parameter
> whose name is in a parameter?

Your first attempt wasn't complicated enough, but your second attempt
was too complicated. :-)

% name=foo
% : ${(P)name::=something}
% print $foo
something
% print $name
foo

The (P)name is interpreted before the ::= so you don't need nested expansion.

References:
- Assign to parameter in parameter -- opposite of ${(P)name}?
  - From: Benjamin R. Haskell

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