Re: _screen calls non-existent program

[Peter Stephenson <Peter.Stephenson@xxxxxxx>]

On Tue, 19 Oct 2010 14:21:12 +0200
Sebastian Stark <seb-zsh@xxxxxxxxxxx> wrote:
> I just noticed that if I try screens completion I am not able to
> select one of many running sessions:
> 
>  screen -S <tab>
> 
> gives an empty set.
> 
> Looking at _screen I see that the list of existing sessions should
> come from
> 
>   _call_program screen-sessions $words[1] -ls
> 
> Now I'm wondering what the screen-sessions command should look like,
> it is not available on any of my machines. To me it looks a bit like
> it is the same as screen itself, because of the -ls option. But than
> I don't get the $words[1] part.
> 
> Any pointers?

"screen-sessions" is just the name to use in the completion context.
The command should be in $words[1], which should be "screen".  "screen
-ls" does the right thing.

The real problem is the completion system hasn't actually been told to
complete a session here. The _arguments specification is:

'-S[name this session <pid>.sockname instead of <pid>.<tty>.<host>]:session name'

which simply outputs "session name", but doesn't try to complete
anything.  This is presumably because it's a new session, so completing
exactly an existing session isn't useful.  However, I can see that
completing an existing session might help you create a new name with
minimal typing. If you change that line (around 84) to

'-S[name this session <pid>.sockname instead of <pid>.<tty>.<host>]:session name:->any-sessions'

you'll get that effect.  It could be a style, I suppose.

-- 
Peter Stephenson <pws@xxxxxxx>            Software Engineer
Tel: +44 (0)1223 692070                   Cambridge Silicon Radio Limited
Churchill House, Cambridge Business Park, Cowley Road, Cambridge, CB4 0WZ, UK


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