Re: Expand array into multiple elements per item?

["Benjamin R. Haskell" <zsh@xxxxxxxxxx>]

On Tue, 13 Sep 2011, Anthony Charles wrote:

> Hi,
>
> You can try this :
> print -l -- "-id "$^somelist
>
> anotherlist=( "-id "$^somelist )
>
> But I can't give you any answer for question 2 :/

anotherlist should end up as I specified before:

    $ anotherlist=( -id 'a b' -id c -id 'd e' )

I.e. separate elements, but not just word-splitting everything:

    $ print -l - $^anotherlist
    -id     <-- separate
    a b     <-- kept as one argument
    -id     <-- separate
    c
    -id     <-- separate
    d e     <-- kept as one argument

With your suggestions the -id isn't a separate element:

    $ print -l - "-id "$^somelist
    -id a b
    -id c
    -id d e
    $ anotherlist=( "-id "$^somelist )
    $ print -l - $^anotherlist
    -id a b
    -id c
    -id d e

--
Best,
Ben