Re: Expand array into multiple elements per item?

["Benjamin R. Haskell" <zsh@xxxxxxxxxx>]

On Tue, 13 Sep 2011, Mikael Magnusson wrote:

> On 13 September 2011 10:57, Peter Stephenson wrote:
> > > Why does neither (i) nor (ii) work?
> >
> > The main problem is that globbing flags rely on globbing; if there's 
> > no matching file, it doesn't work. [...]
>
> One fun thing you can do is use .(e,'reply=(foo bar baz)',) if you 
> want to use some other globbing flags on your data. It's not 
> applicable for this problem, at least I can't think of a way. I did 
> suggest it on irc once for sorting an array by the basename:
>
> 22:39 <offbyone> I want to sort this by basename so that I order the 
> elements in this pair of expansions asciibetically regardless of the 
> directory they're found in.
> 22:39 <offbyone> (so, for example, if I had A/02_something 
> B/01_something B/03_something, it'd come out as B/01_something 
> A/02_something B/03_something)
> 22:47 <Mikachu> a=( oneglob anotherglob )
> 22:47 <Mikachu> echo .(e:'reply=($a)':oe,'REPLY=$REPLY:t',)
>
> It would be nice to have a similar mechanism for sorting arrays maybe :).

+1.


> Oh wait, I just realized it does work, just do this:
>
> % print -l - .(e:'reply=($somelist)':P:-id:)
> -id
> a b
> -id
> c
> -id
> d e
>
> Obviously, this does qualify in the 'a bit of a hack' category. (And 
> yes, it does fail if $PWD is chmoded -x, maybe / is a safer bet.)

Cool.  Nice hack.

--
Best,
Ben