Re: Why the l parameter flag in this case not work?

[Damien Thébault <damien.thebault@xxxxxxxxx>]

On Tue, Mar 20, 2012 at 09:32, lilydjwg <lilydjwg@xxxxxxxxx> wrote:
> I tried to print a line of `-' but not work:
>
> print ${(l.80..-.)}
>
> An empty line is printed. However, printing a line of `=' or other
> strings do work:
>
> print ${(l.80..+.)}
>
> I tried to quote `-', but only 40 `-'s are printed:
>
> print ${(l.80..\-.)}
>

The "print" command is intepreting the expanded expression as an
argument, you can use "echo" or use "--" to tell the "print" command
that the end of arguments has been reached:

echo ${(l.80..-.)}
print -- ${(l.80..-.)}

Regards,
-- 
Damien Thebault