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Re: question about glob qualifier format (#qx)
- X-seq: zsh-users 17984
- From: Peter Stephenson <p.stephenson@xxxxxxxxxxx>
- To: zsh-users@xxxxxxx
- Subject: Re: question about glob qualifier format (#qx)
- Date: Fri, 20 Sep 2013 12:38:30 +0100
- In-reply-to: <20130920111110.GA4501@localhost.localdomain>
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On Fri, 20 Sep 2013 19:11:10 +0800
Han Pingtian <hanpt@xxxxxxxxxxxxxxxxxx> wrote:
> I'm confused about the usage of glob qualifier format "(#qx)". The man
> page says:
>
> ...... Also, as the syntax is unambiguous,
> the expression will be treated as glob qualifiers just as long any
> parentheses contained within it are balanced; appearance of `|', `(' or
> `~' does not negate the effect.
>
> But looks like if I put them in parentheses, it will not take effect any more:
>
>
> $ ls
> 1.c 2.h a b slink
> $ echo *((#q/))
> 1.c 2.h a b slink
>
> So I'd like to know how to comprehend the manpage here? Thanks in
> advance!
Because of the ambiguity between glob qualifiers without the #q and
parenthesised groups, the shell guesses which is which. An expression
containing "|" makes it guess that it's a parenthesised group rather
than a set of glob qualifiers. However, if the *first* open parenthesis
(there's no reason to double them) is followed by #q (and EXTENDED_GLOB
is set), it knows for sure that this is a glob qualifier, so it doesn't
need to do any guessing.
This is there as an additional help; you don't need to change your
normal use of glob qualifiers just because you've signalled them
explicitly with #q. (#q/) works fine.
pws
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