Re: zparseopts default associative array

[Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx>]

On Feb 13,  8:17am, Sebastian Stark wrote:
}
} Maybe I misunderstood something, but isn't my example the intended use
} of -K? Or is the condition "when none of the specs for them is used"
} really meant like "if one option is given, all other default values
} are emptied"? How would this make sense?

Yes, it really does mean that the defaults are kept only if NONE of
the possible options for the array are parsed.  Although it applies to
the default arrays, the intended usage is really with the =array form
as in this snippet of Completion/Base/Core/_description:

    gropt=(-J)
    xopt=(-X)
    nopt=()
    zparseopts -K -D -a nopt 1 2 V=gropt J=gropt x=xopt

In this example -V and -J are mutually exclusive.  (There seem to be a
number of unnecessary uses of -K in the Completion tree.)  Before the
introduction of -K, gropt and xopt would have been unconditionally
erased by having merely been mentioned in the zparsopts arguments.

Yes, it would probably make sense for associative arrays if -K retained
individual elements for associative arrays, but the implementation does
the equivalent of the whole-array assignment o=(-a foo) for both plain
and associative arrays because there is no useful way to do individual
element assignment in the non-associative case.  Unfortunately -K was
an afterthought added with the minimal possible code changes.