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Re: Equivalent of set -- *(DN) in sh
- X-seq: zsh-users 19748
- From: ZyX <kp-pav@xxxxxxxxx>
- To: Eric Cook <llua@xxxxxxx>, "zsh-users@xxxxxxx" <zsh-users@xxxxxxx>
- Subject: Re: Equivalent of set -- *(DN) in sh
- Date: Mon, 19 Jan 2015 18:55:21 +0300
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19.01.2015, 18:51, "ZyX" <kp-pav@xxxxxxxxx>:
> 18.01.2015, 23:53, "Eric Cook" <llua@xxxxxxx>:
>> On 01/18/2015 01:28 PM, Nikolai Weibull wrote:
>>> Hi!
>>>
>>> Is there any way to get the equivalent of Zsh’s
>>>
>>> set -- *(DN)
>>>
>>> in sh? Most important here would be NULL_GLOB, as, by default, sh
>>> simply leaves the * if there are no files to match.
>>>
>>> Thanks!
>> match() {
>> test "$#" -gt 2 && return
>> test -e "$1" && return
>> return 1
>> }
>>
>> set --
>> for pat in '.[^.]*' '*'; do # *(DN) ignores . and ..
>
> `..foo` is a valid name, but it is being excluded. You need to add `'.??*'` to the list of patterns.
No, this may make duplicates. Then `'..?*'`.
>> if match $pat; then
>> set -- "$@" $pat
>> fi
>> done
>> unset pat
>>
>> test "$#" -gt 0 && printf '%s\n' "$@"
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