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Re: parameter expansion with '$'
# ak@xxxxxxxxxxxx / 2015-02-25 12:50:16 -0800:
> I'd like to only perform the substitution when 'c' occurs at the
> end of the string:
>
> $ echo ${X/c$/}
> abc # I'd like this to return 'ab' like above
>
> I assume others see the same results? Can anybody help me understand why it
> doesn't work, and how I can interpret the '$' as a regular expression
> wildcard rather than some other sort of zsh sigil?
these patterns are *not* regular expressions. zshexpn(1) says near
the start of PARAMETER EXPANSION:
In the expansions discussed below that require a pattern, the form
of the pattern is the same as that used for filename generation; see
the section `Filename Generation'.
${name/pattern/repl}
${name//pattern/repl}
[...]
The pattern may begin with a `#', in which case the pattern must
match at the start of the string, or `%', in which case it must
match at the end of the string, or `#%' in which case the pat-
tern must match the entire string. [...] Note also that the `#',
`%' and `#%' are not active if they occur inside a substituted
parameter, even at the start.
--
roman
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