convert sed to zsh

[Ray Andrews <rayandrews@xxxxxxxxxxx>]

I'm trying to convert a 'sed' filter to native zsh.  Here's the sed:

    bar=$( echo $foo |
    sed -r "s/\x1B\[([0-9]{1,2}(;[0-9]{1,2})?)?[mGK]//g" )

Here's my candidate zsh:

    bar=$foo//$'\x1B'\[([0-9](#c0,2)(;[0-9](#c0,2))#)#[mGK]/}

... so far it's working, but I'm nervous about it.  In another context 
it seems I have to backslash the semi-colon, but here it seems ok either 
way, but of course it should be one or the other. The 'sed' is of course 
the kosher way (I believe) of removing color codes and various other 
escapes like "\e[K" that seem to hang around colorized output of 'grep' 
and so on.  With several different forms of color codes, I want to be 
sure I get this right. Unless of course zsh already has a stock way of 
stripping escape sequences, which it very well might.