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Re: CONDITIONAL EXPRESSIONS, string == pattern
> On Jul 24, 2021, at 11:30 PM, Eric Cook <llua@xxxxxxx> wrote:
>
> so in:
>
> eval echo 'test ${vs} == ${vp} && echo hi || echo lo'
>
> zsh does the normal expansions of the line and passes the arguments to eval, since the single quotes prevented
> any possible expansions the result is:
>
> echo test ${vs} == ${vp} && echo hi || echo lo
>
> so the above line goes through the steps of expansions and ends up like so:
>
> echo test ' str1 a2' '==' '[[:blank:]]##str1[[:blank:]]##[[:alnum:]][[:alnum:]]' && echo hi || echo lo
>
> so /echo/ prints out the strings given to it, which succeeds, causing echo hi to run.
I'll just add that examining the full contents of 'r' would have
provided a big hint that 'test' wasn't being run at all.
% cat /tmp/testing2.zsh
setopt EXTENDED_GLOB NO_EQUALS
vs=' str1 a2'
vp='[[:blank:]]##str1[[:blank:]]##[[:alnum:]][[:alnum:]]'
r=( ${(f)"$( eval echo 'test ${vs} == ${vp} && echo hi || echo lo' )"} )
typeset -p r
% zsh -f /tmp/testing2.zsh
typeset -a r=( 'test str1 a2 == [[:blank:]]##str1[[:blank:]]##[[:alnum:]][[:alnum:]]' hi )
--
vq
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