On Tue, Sep 28, 2021, at 3:54 PM, Pier Paolo Grassi wrote:
> on 5-8 I get:
>
>> a=(sa\ bb cc\ dd); a=${(qqq)a}
>> typeset -p a
> typeset a='"sa bb cc dd"'
Perhaps it should have been ${(qqq@)a}?
% a=(sa\ bb cc\ dd); typeset -p a
typeset -a a=( 'sa bb' 'cc dd' )
% b=${(qqq@)a}; typeset -p b
typeset b='"sa bb" "cc dd"'
--
vq