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Re: (z) expansion flag do not always return an array

X-seq: zsh-users 27388
From: Vincent Bernat <bernat@xxxxxxxx>
To: Roman Perepelitsa <roman.perepelitsa@xxxxxxxxx>
Cc: Zsh Users <zsh-users@xxxxxxx>
Subject: Re: (z) expansion flag do not always return an array
Date: Mon, 29 Nov 2021 18:44:18 +0100
Archived-at: <https://zsh.org/users/27388>
In-reply-to: <CAN=4vMpHw6m23qLyy3kurDgXvs1nRW6XAs3FEUQc7wX-Jpzysw@mail.gmail.com> (Roman Perepelitsa's message of "Mon, 29 Nov 2021 17:34:14 +0100")
List-id: <zsh-users.zsh.org>
References: <m3k0grdlls.fsf@luffy.cx> <CAN=4vMpHw6m23qLyy3kurDgXvs1nRW6XAs3FEUQc7wX-Jpzysw@mail.gmail.com>

 ❦ 29 November 2021 17:34 +01, Roman Perepelitsa:

>> Is there an easy way to know if something is an array or a string?
>> I am  using subscripting for that but maybe there are better ways.
>
> If you had a parameter, you could use ${(t)foo} or $parameters[foo] to
> find its type. However, if you had a parameter you wouldn't have this
> problem to begin with.

Thanks for the tips!

>   foo=(${(z)...})
>
> Here foo is always an array.

Yes, that's what I have done.
-- 
Let the machine do the dirty work.
            - The Elements of Programming Style (Kernighan & Plauger)

References:
- (z) expansion flag do not always return an array
  - From: Vincent Bernat
- Re: (z) expansion flag do not always return an array
  - From: Roman Perepelitsa

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