Re: possible bug in zsh concerning a for loop

[Vincent Lefevre <vincent@xxxxxxxxxx>]

On 2022-03-18 17:45:22 +0900, Jun T wrote:
> You can get this by:
> 
> [1] use array (instead of scalar parameter items)
> 
> a=( item1 item2 item3 )
> for i in $a; do ... done
> 
> [2] use ${=items}
> 
> for i in ${=items}; do ... done
> 
> [3] set SH_WORD_SPLIT option
> 
> setopt SH_WORD_SPLIT
> for i in $items; do ... done
> 
> I prefer [1], but it is up to you which method you use.

[1] has the advantage that it supports arguments containing spaces.

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Vincent Lefèvre <vincent@xxxxxxxxxx> - Web: <https://www.vinc17.net/>
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