Hi!
I am trying to get the last word of LBUFFER.
What I did previously was:
${${(z)LBUFFER}[-1]}
This worked flawlessly until I noticed today that it misbehaves if LBUFFER
contains only one word. In this case it seems like `[-1]` acts on a scalar, as
it expands to the last character instead of LBUFFER as I would expect.
Is this expected behaviour?
I now work around it by prepending LBUFFER with a dummy word so that it always
has at least two words (I know that it is not empty). But this feels very hacky.
Do you know of a better way?
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