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Re: can print but not assign to variable




On 2022-10-26 14:57, Lawrence Velázquez wrote:

What do you call that construction?  I know "(( ))" and "$(( ))" and
"$()" but I don't really know that one tho I've used it a few times on
faith.  As usual, if I knew what it was called I'd read up on it.

Ah!  Yes, I do know that.  Yes, we must force 'var' to become an array.  Stupid ... when I'm doing it with understanding, I get "( )" just fine, but when I don't get the necessity I'm lost :(  Ok, all clear.

Tx Roman and Lawrence.



It's just an array assignment.  See zshparam(1).

You originally attempted to do a simple scalar assignment, for which
globbing is not performed on the right-hand side.





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