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Re: Why no $match for parens inside a ~^ ?



PS. (#b) is missing in the pattern, correct code is:
[[ "zparseopts -F" == (#b)*(zparseopts)*~^*(-F)* ]]
printf →%s\\n $? "$match[@]"

output is the same.


On Wed, 25 Jan 2023 at 14:50, Sebastian Gniazdowski <sgniazdowski@xxxxxxxxx> wrote:
Hi,
I'm matching a pattern:
[[ "zparseopts -F" == *(zparseopts)*~^*(-F)* ]]
printf →%s\\n $? "$match[@]"

with output:
→0
→zparseopts


I would want \3 to contain -F… because, I would once want to use (-F|) there, and be able to test if the option is given… Is it possible? 

~^ is a double negation that makes the pattern work like "if-contains zparseopts AND -F"


--
Best regards,
Sebastian Gniazdowski



--
Best regards,
Sebastian Gniazdowski



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