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Re: Remove multiple characters after match

X-seq: zsh-users 29382
From: Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx>
To: Jörg Sommer <joerg@xxxxxxxx>
Cc: zsh-users@xxxxxxx
Subject: Re: Remove multiple characters after match
Date: Wed, 20 Dec 2023 14:28:35 -0800
Archived-at: <https://zsh.org/users/29382>
In-reply-to: <molzf7qu3w4q5bf7gdybj3fmp5p2sursypac3mjogtc6sqnjvu@a2jp2ge72tzl>
List-id: <zsh-users.zsh.org>
References: <molzf7qu3w4q5bf7gdybj3fmp5p2sursypac3mjogtc6sqnjvu@a2jp2ge72tzl>

On Mon, Dec 18, 2023 at 11:34 PM Jörg Sommer <joerg@xxxxxxxx> wrote:
>
> How can I remove the spaces after the left delimiter?

You're trying to get the shortest match for (*) and the longest match
for ( #), which doesn't work.  I think your best bet is to first
remove all the spaces around delimiters:

${(*)x// #,, #/,,}

And then leave space matching out of the # and % constructions:

% print -l -- -${(*)^${(*)${(*)x// #,, #/,,}#*,,}%,,*}-
-*.i-
-*.i-
-*.i-
-*.i-
-*.i-
-*.i-

You didn't actually say what output you wanted but I think that's it?

Follow-Ups:
- Re: Remove multiple characters after match
  - From: Jörg Sommer

References:
- Remove multiple characters after match
  - From: Jörg Sommer

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