Re: nesting issue

[Ray Andrews <rayandrews@xxxxxxxxxxx>]

On 2024-05-05 13:14, Lawrence Velázquez wrote:

> Nonsense.  There is no universally desired sort.  It depends entirely on what the application needs.
    Naturally, but I expect that when we are sorting numbers, '2' should
    come before '10' most of the time.  No not 'everybody' but ...
    sheesh, I'm just saying that I'm glad that '(n)' gives me what I'd
    call version sort.  That's all.  Can't I be satisfied?
> I don't see this behavior.
> ...
> 	aaa,3,pard
> 	aaa,3a,pard
>
>     
    8 /aWorking/Zsh/Source/Wk/Boneyard 1 % var=(
      aaa,3*(nN) ); print -l $var       
      aaa,3a,pard
      aaa,3,pard
      
      ... I don't know what to say.
      
      8 /aWorking/Zsh/Source/Wk/Boneyard 1 % var=( aaa,6*(nN) ); print
      -l $var
      aaa,6
      aaa,6,    # sixth char ',' precedes sixth char 'a'
      aaa,6a
      aaa,6a,
      aaa,6a,howdy    # sixth char 'a'
      precedes sixth char ','
    aaa,6,howdy
    
    It's not how I understand sorting but I don't doubt there is some
    method to it.  'sort' does the same.  'sort' has been around a long
    time so I don't doubt that what it does is very well thought out
    whether it makes sense to me or not.   Version sort is not a strict
    'dictionary' sort, it 'interprets', so the above does what it thinks
    best.  I would have expected:
    
    aaa,6,    
      aaa,6a
    aaa,6,howdy
    aaa,6a,howdy 
      
      ... but that's not the way it is. Not worth worrying about.
      
      vmlinuz-6.1.0-20-amd64
      
      ... that's my Linux version, the algorithm for sorting such
      versions must be a bit arbitrary.  I'm not complaining.