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RE: Bug in filename expansion
- X-seq: zsh-workers 1413
- From: Ray_Van_Tassle-CRV004@xxxxxxxxxxxxx
- To: hzoli@xxxxxxxxxx (Receipt Notification Requested), rayvt@xxxxxxxxxxxxxxxxxx (Receipt Notification Requested)
- Subject: RE: Bug in filename expansion
- Date: 21 Jun 96 10:26:27 -0500
- Cc: zsh-workers@xxxxxxxxxxxxxxx (Receipt Notification Requested)
[[ example deleted ]]
> No, it isn't wrong. ^pattern matches if pattern does not match. You
should
> use groupping.
>
> zz^(a|b)yy is the same as zz^((a|b)yy) and zz(^(a|b))yy is what you want.
>
> Zoltan
>
No, that doesn't work either. Also, if my 1st attempt ("zz^(a|b)yy") is
incorrect, this is a surprise, and it should probably be mentioned in the
documentation. Or maybe the precedence of "^" changed ?
If there isn't a bug here (and I think there is), then we need some
further examples of "how to do it".
Also.... how can I do a parenthisised group at the *end* of a pattern? It
thinks that this is a "list of qualifiers".
Here's my trial script & output:
setopt verbose
touch zzayy
touch zzbyy
touch zzxyy
ls zz*
zzayy
zzbyy
zzxyy
#next works--shows a & b
ls zz(a|b)yy
zzayy
zzbyy
#next doesn't work--should show x
ls zz^(a|b)yy
./try: no match [9]
# zoltan says the above means the same as next
ls zz(^(a|b)yy)
./try: no match [11]
# zoltan says this will show x. but it doesn't
ls zz(^(a|b))yy
./try: no match [13]
unsetopt verbose
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