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Re: RC_EXPAND_PARAM bug
- X-seq: zsh-workers 3395
- From: "Bart Schaefer" <schaefer@xxxxxxxxxxxxxxxx>
- To: Zoltan Hidvegi <hzoli@xxxxxxxxxxxxxxx>
- Subject: Re: RC_EXPAND_PARAM bug
- Date: Wed, 30 Jul 1997 00:33:23 -0700
- Cc: zsh-workers@xxxxxxxxxxxxxxx (Zsh hacking and development)
- In-reply-to: <199707300651.CAA01564@xxxxxxxxxx>
- References: <199707300651.CAA01564@xxxxxxxxxx>
On Jul 30, 2:51am, Zoltan Hidvegi wrote:
} Subject: Re: RC_EXPAND_PARAM bug
}
} If `a' is empty, you want $^a/* expand to nothing, otherwise you would
} get the list of files in the root directory which you do not want.
} Such tricks are used in several zsh scripts I guess, and this is the
} preferable behaviour. And it always worked this way, that's the point
} where there is not difference between versions.
That's fine, then.
} One might require the evaluation of the suffix even if it is discarded
} later. Do you think it is preferable?
I think perhaps it is, especially if the suffix contains arithmetic or
command substitutions that might have side effects.
} > What does the real "rc" shell do?
}
} I do not think this has anything to do with rc.
I'm pretty sure that it does. All the RC_ options are things that "rc"
does, just like the CSH_ options are things CSH_ does, and KSH_, etc.
I believe Paul originally named all the options that were borrowed from
other shells by that convention.
} > } It looks illogical. Either the latter should be 'ax b1x ay b1y' or the
} > } former 'a1x b1x y'.
} >
} > I agree with Andrej on that. If you're going to map over lists, you
} > have to map over them in the prefix too, not just in the suffix.
} >
} > However, I don't like the behavior of (3), i.e. that when ${x} is a list
} > then the word break interrupts the rc-expansion. I'd prefer that the
} > expansion proceed across the suffix in the same way regardless of whether
} > x is an array or a string, and then introduce the word breaks at the end.
}
} I do not understand exatly what you mean, but I'm leaning towards option
} 3.
Consider:
a=(a b)
c="c d"
e=(e f)
${^a}${c}${^e} --> "ac de" "bc de" "ac df" "bc df"
Now:
c=(c d)
Option 2: ${^a}${c}${^e} --> ac de bc de ac df bc df
Option 3: ${^a}${c}${^e} --> ac bc de df
I like the symmetry between (2) and the case where c is a string.
--
Bart Schaefer Brass Lantern Enterprises
http://www.well.com/user/barts http://www.brasslantern.com
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