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Re: RC_EXPAND_PARAM final patch
- X-seq: zsh-workers 3404
- From: "Bart Schaefer" <schaefer@xxxxxxxxxxxxxxxx>
- To: Zoltan Hidvegi <hzoli@xxxxxxxxxxxxxxx>, zsh-workers@xxxxxxxxxxxxxxx (Zsh hacking and development)
- Subject: Re: RC_EXPAND_PARAM final patch
- Date: Sat, 2 Aug 1997 12:28:13 -0700
- In-reply-to: <199708020727.DAA03172@xxxxxxxxxx>
- References: <199708020727.DAA03172@xxxxxxxxxx>
On Aug 2, 3:27am, Zoltan Hidvegi wrote:
} Subject: RC_EXPAND_PARAM final patch
}
} There is still one point where the behaviour might be surprising: that's
} when the (e) substitution flag is used:
}
} % echo ${x}1${(e)^a}2${x}
} x y1a2x y y1b2x y
I get very strange behavior from this. Vis:
zagzig<25> a=('$[i++]' '$[i++]' '$[i++]')
zagzig<26> i=0
zagzig<27> echo ${^x}1${a}2${^x}
x1$[i++] y1$[i++] z1$[i++] $[i++] $[i++]2x $[i++]2y $[i++]2z
OK so far, but:
zagzig<28> i=0
zagzig<29> echo ${^x}1${(e)a}2${^x}
x10 y10 z10 $[i++] $[i++]2${^x}
Huh? Why didn't it evaluate the second ${^x}, which is unquoted and at
the same (re)interpretation level as the first ${^x} ? I would at least
have expected to get
x10 y10 z10 $[i++] $[i++]2x $[i++]2y $[i++]2z
--
Bart Schaefer Brass Lantern Enterprises
http://www.well.com/user/barts http://www.brasslantern.com
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