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Re: Z-Shell (zsh) FAQ changes this month

X-seq: zsh-workers 5691
From: Phil Pennock <comet@xxxxxxxx>
To: Zsh Development Workers <zsh-workers@xxxxxxxxxxxxxx>
Subject: Re: Z-Shell (zsh) FAQ changes this month
Date: Tue, 9 Mar 1999 00:53:25 +0000
In-reply-to: <9902250957.AA30563@xxxxxxxxxxxxxxxxx>; from "Peter Stephenson" on Thu 25 Feb 1999 (10:57 +0100)
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Mailing-list: contact zsh-workers-help@xxxxxxxxxxxxxx; run by ezmlm
Organisation: Organisation? Here? No, over there ---->
References: <9902250957.AA30563@xxxxxxxxxxxxxxxxx>

Okay, I've caught up on everything and not seen anything on this, so...

Typing away merrily, Peter Stephenson produced the immortal words:
> 3.22: How do I get a variable's value to be evaluated as another variable?
> 
>   The problem is that you have a variable $E containing the string
>   `EDITOR', and a variable $EDITOR containing the string `emacs',
>   or something such.  How do you get from $E to emacs in one easy
>   stage?
> 
>   There is no standard single-stage way of doing this.  However, there
>   is a zsh idiom (available in all versions of zsh since 5.0) for this:


zsh 5.0 already?  I wasn't busy _that_ long.
-- 
--> Phil Pennock ; GAT d- s+:+ a23 C++(++++) UL++++/I+++/S+++/B++/H+$ P++@$
L+++ E-@ W(+) N>++ o !K w--- O>+ M V !PS PE Y+ PGP+ t-- 5++ X+ R !tv b++>+++
DI+ D+ G+ e+ h* r y?

Follow-Ups:
- Re: Z-Shell (zsh) FAQ changes this month
  - From: Geoff Wing

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