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Re: compctl -v
- X-seq: zsh-workers 5749
- From: Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx>
- To: Bernd Eggink <eggink@xxxxxxxxxxxxxx>
- Subject: Re: compctl -v
- Date: Wed, 10 Mar 1999 22:32:44 -0800 (PST)
- Cc: Zsh-workers <zsh-workers@xxxxxxxxxxxxxxx>
- In-reply-to: <36E6D2CC.7CFCB1DA@xxxxxxxxxxxxxx>
- Mailing-list: contact zsh-workers-help@xxxxxxxxxxxxxx; run by ezmlm
- References: <36E6D2CC.7CFCB1DA@xxxxxxxxxxxxxx>
- Reply-to: Bart Schaefer <schaefer@xxxxxxxxxxx>
Bernd Eggink writes:
> compctl -D -v
This means that all default completions should use parameter names and
only parameter names, which is probably not what you intended.
> these commands are nicely completed:
>
> vared xyz<TAB>
> print $xyz<TAB>
Completion following a $ is a special case and doesn't require compctl
to activate it.
> ls xyz<TAB>
>
> all shell parameters starting with 'xyz' also show up, which IMHO is
> nonsense. Any way to prevent this, and get parameter names completed
> only if preceded by '$' or 'vared'?
Yes; you want to get rid of that compctl -D, and instead use
compctl -v vared
A minimal set of sensible compctls using only built-in completions is:
compctl -B builtin
compctl -m command
compctl -v declare integer local readonly read
compctl -aBFw disable
compctl -daBFw enable
compctl -c exec sched whence where -
compctl -F functions unfunction
compctl -Nv getln
compctl -a unalias
compctl -cn unhash
compctl -k signals trap
# These last few are enabled by default in 3.0, but not in 3.1.2 and later
compctl -b bindkey
compctl -v export typeset unset vared
compctl -o setopt unsetopt
compctl -c which
The argument for leaving out all default compctls from 3.1.2+, last time I
heard it, is that the above set isn't "good enough" by comparison to the
collection in Misc/compctl-examples to be worth having. I've been saying
for at least a year now that I think that's a silly reason to have zsh
out-of-the-box default to completing nothing but file names, but I guess
I'm beating a dead horse.
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