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Re: Getting rid of temporaries...

    Hi Bart :)

 * Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx> dixit:
> }   [[ -z 'foo.<28->.jpg(N[2])' ]]
> } which is no use.
> It's not eval that quotes that, it's [[ ]].

    Oh :(((

> So without the function, it's
> print -l *.??.jpg(e@'eval "[ -z ${~REPLY:r:r}.<${~REPLY:r:e}->.jpg(N[2]) ]"'@)
> where @ is chosen as a character that appears nowhere in the expression.

    Thanks a lot for the expressión :))))

    Raúl Núñez de Arenas Coronado

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