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Re: Bug or misundertanding from my part?

DervishD wrote:
>     Hi all :)
>     In the ZSH manual for 4.2.5 we can read:
> { TRY-LIST } always { ALWAYS-LIST }
>      First execute TRY-LIST.  Regardless of errors, or break, continue,
>      or return commands encountered within TRY-LIST, execute
>      ALWAYS-LIST.  Execution then continues from the result of the
>      execution of TRY-LIST; in other words, any error, or break,
>      continue, or return command is treated in the normal way, as if
>      ALWAYS-LIST were not present.  The two chunks of code are referred
>      to as the `try block' and the `always block'.
>     So, this code should print "try list" and "always list", but it
> doesn't:
>     #!/bin/zsh
>     emulate -L zsh
>     {
>         print "try list"
>         return 13
>     } always {
>         print "always list"
>         return 0
>     }
>     print "What?"
>     The code above just prints "try list" and exits with a return
> code of "13", but the manual says that the ALWAYS-LIST is executed
> "Regardless of [...] return commands encountered [...]". Am I doing
> something wrong? I'm a bit puzzled because the above works if I
> change 'return 13' for 'false'.

You're running this as a script, right?  In that case the returns are treated
as exits, which have an immediate effect.  To treat returns as returns
you need a function.


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