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Re: Is this a bug? Why not?
- X-seq: zsh-workers 27850
- From: Bart Schaefer <schaefer@xxxxxxxxxxxxxxxx>
- To: zsh-workers@xxxxxxx
- Subject: Re: Is this a bug? Why not?
- Date: Wed, 31 Mar 2010 08:11:53 -0700
- In-reply-to: <20100331060602.GA91691@xxxxxxxxxxxxxxxxxxxx>
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Incidentally, this came up because of a discussion on the POSIX standards
mailing list (austin-group) in which David Korn just asserted that he'd
like to add the syntax ${"var"} which means to expand the value of var
as if it's quoted (what zsh's normal mode does all the time).
This differs from "${var}" because you can write ${"var"-*} and get the
value of $var quoted but the glob pattern unquoted. Apparently the old
Bourne shell allows the abominable "${var"-*} (note quote placement
overlapping with brace placement) to accomplish this.
I was hoping to be able to say "Oh, zsh already has syntax XYZ for that"
but in fact we don't -- zsh either always, or never, does it, depending
on the globsubst option; there's no way to flip globsubst on the fly.
On Mar 30, 11:06pm, Phil Pennock wrote:
} Subject: Re: Is this a bug? Why not?
}
} So the string ${var} when treated as a variable-name is empty but
} defined? The four expansions with a nested ${var} are entirely
} consistent with the behaviour when expanding a variable which is
} defined with a value of length 0.
}
} Seems unusual, but consistent.
Indeed. OK, I can live with that, as it's been that way forever.
} In bash, ksh, bad substitution. In ksh93, it gets weird:
} $ echo ${var-???}
} OSM SCM bin dbg doc etc lib man src tmp www
} $ echo ${${var}-???}
} ksh93: syntax error: `!' unexpected
That is weird, but AFAIK only zsh of all shells allows wrapping ${...}
in another ${...} as valid syntax, so this may just be an error ksh93
didn't catch.
} The ksh reference-name expansion made me think of the somewhat opposite
} expansion in zsh, (P)var ...
}
} Hrm, zsh 4.3.10 1.4705:
}
} % print ${(P)-???}
} zsh: 0239BCJPXZgiklms: ??
}
} Strange that the first entry is somehow tying into expanding $- for the
} shell options ...
Actually that makes perfect sense; only the :- and :+ forms are doc'd
as working with a missing parameter name, so ${(P)-} really does mean
to grab the value of $- and try to use that as a parameter name. It
otherwise has to behave like ${-?string}.
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