Reply to message «Re: Check existence of a program»,
sent 22:12:09 01 February 2011, Tuesday
by ZyX:
Sorry, I should have read your question more correctly (and test $(cmd) variant
better). $(cmd) actually propagates exit code, so the reason is overriding of
$path as others have mentioned.
Original message:
> Reply to message «Check existence of a program»,
> sent 21:29:11 01 February 2011, Tuesday
> by Anonymous bin Ich:
>
> prog=exiftime
> path==$prog
> if [[ $? -ne 0 ]] ; then
> prog=identify
> path==$prog
> endif
>
> It works because zsh takes first = as assignment operator and expands
> second `=$prog' construct into a full path. If `=$prog' expansion fails,
> it throws an exception, exception prevents variable from being set and
> thus last expression fails what is indicated in $?.
>
> If you use $(cmd) construct, then though `cmd' fails, $(cmd) that does not
> care about exit code just expands into output of `cmd', so last expression
> (which is variable assignment, NOT `cmd') does not fail. Also note that
> `=$prog' does not produce new fork.
>
> Original message:
> > Hello!
> >
> > I am having trouble checking for existence of a program.
> >
> > This works:
> >
> > % cat working.zsh
> > #!/bin/zsh
> > set -x
> > prog="identify"
> > path=$(which ${prog})
> > %
> > % ./working.zsh
> > +./working.zsh:3> prog=identify
> > +./working.zsh:4> path=+./working.zsh:4> which identify
> > +./working.zsh:4> path=/usr/bin/identify
> > %
> >
> > But this doesn't:
> >
> > % cat notworking.zsh
> > #!/bin/zsh
> > set -x
> > prog="exiftime"
> > path=$(which ${prog})
> > if [[ ${?} -ne 0 ]]; then
> >
> > prog="identify"
> > path=$(which ${prog})
> >
> > fi
> > %
> > % ./notworking.zsh
> > +./notworking.zsh:3> prog=exiftime
> > +./notworking.zsh:4> path=+./notworking.zsh:4> which exiftime
> > +./notworking.zsh:4> path='exiftime not found'
> > +./notworking.zsh:5> [[ 1 -ne 0 ]]
> > +./notworking.zsh:6> prog=identify
> > +./notworking.zsh:7> path=+./notworking.zsh:7> which identify
> > +./notworking.zsh:7> path='identify not found'
> > %
> >
> > Any idea?
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