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set -e (no && or ||)

X-seq: zsh-workers 30727
From: "Sergey Fadeev" <hindsight@xxxxxxxxx>
To: zsh-workers@xxxxxxx
Subject: set -e (no && or ||)
Date: Fri, 12 Oct 2012 07:05:41 -0400
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Why doesn't it exit the shell?
 $ set -e
 $ echo $(false)
 Shouldn't the error code of $(false) command substitution be checked by set -e before passing stdout to the echo builtin?
 Isn't it the most logical behavior that most people would expect of set -e?
 Zsh version: zsh 4.3.17 (x86_64-redhat-linux-gnu) (if it matters)
 Thanks

Follow-Ups:
- Re: set -e (no && or ||)
  - From: Peter Stephenson

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