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%? glob hack



There's some code that makes %? not treat the ? as a wildcard because
it's job string lookup syntax, however I feel like that's not really
necessary? If someone really uses that a lot and is bothered by having
to quote the ?, they could just alias fg/bg to noglob fg/bg, or use
whatever the bash-esque option to keep failed globs is called. Or am I
missing something here?

-- 
Mikael Magnusson



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