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Re: [BUG] functions can't create global readonly variables
Bart Schaefer schreef op 02-01-16 om 05:27:
> On Jan 2, 4:27am, Martijn Dekker wrote:
> } I don't know if this is intended behaviour for native zsh mode; the
> } 'zshbuiltins' man page does not mention anything about this.
>
> Of course it does:
I blame insufficient caffeination at the time of writing.
> } But it is certainly a bug for POSIX/'emulate sh' mode.
>
> I think it's undefined behavior for POSIX/'emulate sh'. Certainly bash
> agrees with us:
>
> $ foo() { typeset -r bar; typeset -p bar; }
> $ foo
> declare -r bar
> $ typeset -p bar
> bash: typeset: bar: not found
But 'typeset' is not POSIX. When using the POSIX 'readonly' special
builtin, bash acts like other POSIX shells and unlike zsh:
$ foo() { readonly bar=baz; typeset -p bar; }
$ foo
declare -r bar="baz"
$ typeset -p bar
declare -r bar="baz"
Thanks,
- M.
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