"set -e" handling is broken with zsh 5.3.1 and 5.4.1

[Vincent Lefevre <vincent@xxxxxxxxxx>]

Consider:

----------------------------------------
#!/usr/bin/env zsh

set -e

f()
{
  [[ -z 1 ]] && false
}

if false; then
  :
else
  f
  echo Fail 1
  echo Fail 2
  f
  echo Fail 3
fi
----------------------------------------

With
  zsh 5.3.1-4+b1 under Debian/stretch
  zsh 5.4.1-1 under Debian/unstable

I get:

% ./cond2-e; echo $?
Fail 1
Fail 2
1

I suppose that cond2-e should die just after f is called, before
outputting anything. At least, the behavior is not consistent.

zsh 5.0.7 was outputting:

Fail 1
Fail 2
Fail 3

but I suppose that this was incorrect (different from what other
shells give on similar POSIX code).

-- 
Vincent Lefèvre <vincent@xxxxxxxxxx> - Web: <https://www.vinc17.net/>
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Work: CR INRIA - computer arithmetic / AriC project (LIP, ENS-Lyon)