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using trap function to cleanup and exit?
- X-seq: zsh-workers 50022
- From: Greg Klanderman <gak@xxxxxxxxxxxxxx>
- To: Zsh list <zsh-workers@xxxxxxx>
- Subject: using trap function to cleanup and exit?
- Date: Sun, 10 Apr 2022 11:46:25 -0400
- Archived-at: <https://zsh.org/workers/50022>
- List-id: <zsh-workers.zsh.org>
- Reply-to: Greg Klanderman <gak@xxxxxxxxxxxxxx>
Hi,
I've been trying to ensure some cleanup is done when a script I'm
writing exits, whether normally, with an error, or when killed (other
than with -9, of course).
I had thought a try/always block would handle signals as well, but
it appears not.
So I've been trying to use either trap functions or the trap builtin
(list traps) with no success.
[zsh below is debian/5.8.1-1 (Debian testing)]
Here's a simple test script (the sleep has been substituted for an
external command that waits on a condition and outputs something; my
actual use case also has that within a loop):
<script>
#!/bin/zsh -f
cleanup () {
echo "cleanup"
}
do_something () {
echo "in do_something"
local foo
read -u 0 foo
echo "done do_something"
}
TRAPTERM () {
echo "in TRAPTERM"
cleanup TERM
exit $(( 128 + $1 ))
}
foo () {
echo "in foo"
sleep 1234567 | do_something
}
foo
</script>
When run, it immediately prints:
| in foo
| in do_something
then when hit with SIGTERM:
| in TRAPTERM
| cleanup
however, the process and its child (sleep) remain running.
I expected both to exit.
Additionally, when I hit it with some other signal (SIGINT), the
script does get killed, however, the child sleep process remains.
Is that expected?
I tried TRAPEXIT as well, both at top level and within the function
foo, but that seems not to handle signals.
How can I ensure that a script and non-disowned children are killed
when a signal is received, after doing some cleanup?
Is there a way to do that for all appropriate signals, or do I have to
explicitly list the desired signals?
thank you,
Greg
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