Re: problem with 'ls | less' shell function

[Mikael Magnusson <mikachu@xxxxxxxxx>]

On 10/17/22, Thomas Klausner <wiz@xxxxxxxxxxx> wrote:
> Hi!
>
> I recently noticed a problem in zsh 5.9 (as built from pkgsrc) on
> NetBSD 9.99.100. Since I didn't notice it before it could be related
> to a change in NetBSD (I'm following the latest version), but I've
> been told that the issue can be reproduced on Ubuntu 19.04 and FreeBSD
> 13.1 too; but not in zsh 5.8.1, nor in most other shells though.
>
> The discussion on the NetBSD mailing list can be read in this thread:
> https://mail-index.netbsd.org/current-users/2022/10/12/msg043076.html
> but I'll summarize the issue I see in zsh here.
>
> I have a shell function I've been using for ages:
>
> dir() { ls -al "$@" | less; }
>
> Recently, when I tried suspending this with CTRL-Z and then resuming
> it with 'fg', I get:
>
> $ dir
> (CTRL-Z)
> zsh: done       ls -al "$@" |
> zsh: suspended
> $ fg
> [1]  + done       ls -al "$@" |
>        continued
> zsh: done                    ls -al "$@" |
> zsh: suspended (tty output)
> zsh: done                    ls -al "$@" |
> zsh: suspended (tty output)
>
> The same thing works in NetBSD's ksh:
>
> $ fg
> ls -al "$@" | less
> (CTRL-Z)
> [1] + Done                 ls -al "$@" |
>       Stopped              less
>
> or in bash
>
> $ fg
> ls -al "$@" | less
> (CTRL-Z)
>
> [1]+  Stopped                 ls -al "$@" | less
>
> If I use '/bin/ls' in the shell function instead of 'ls', it works
> fine.
>
> Any ideas what the issue could be?

The last bit implies that 'ls' is an alias or function, can you check
the output of 'which ls'?

-- 
Mikael Magnusson