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Re: compinit error when IFS is \n
- X-seq: zsh-workers 53467
- From: Lawrence Velázquez <larryv@xxxxxxx>
- To: "Avid Seeker" <avidseeker@xxxxxxxxxxx>
- Cc: "Bart Schaefer" <schaefer@xxxxxxxxxxxxxxxx>, zsh-workers@xxxxxxx
- Subject: Re: compinit error when IFS is \n
- Date: Sat, 12 Apr 2025 21:56:12 -0400
- Archived-at: <https://zsh.org/workers/53467>
- Feedback-id: iaa214773:Fastmail
- In-reply-to: <D953LHRUVWMR.3O4MD2WVMWMIG@disroot.org>
- List-id: <zsh-workers.zsh.org>
- References: <D91O58LD38KJ.CLO5X66T4DSZ@disroot.org> <CAH+w=7aPE2xMX7i+26UBCdYixZqSZzcUdbWGKhx7OfdFTGyKjQ@mail.gmail.com> <D953LHRUVWMR.3O4MD2WVMWMIG@disroot.org>
On Sat, Apr 12, 2025, at 8:52 PM, Avid Seeker wrote:
> See the original discussion I linked:
> https://github.com/gokcehan/lf/discussions/1947
It's unhelpful to say "this doesn't work" and dump two external
discussions that you expect others to comb through, without even
providing a minimal reproducer.
https://github.com/gokcehan/lf/discussions/1947#discussioncomment-12740050
However, the `set -- $fx` part doesn't work for some
reason. It combines all of $fx in $1 as one string.
Which doesn't make sense for me.
zsh doesn't split variable expansions by default.
--
vq
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