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Re: 4.1.1: three bugs?
- X-seq: zsh-users 6421
- From: Wayne Davison <wayned@xxxxxxxxxxxxxxxxxxxxx>
- To: GoTaR <gotar@xxxxxxxxxxxxxx>
- Subject: Re: 4.1.1: three bugs?
- Date: Tue, 29 Jul 2003 02:51:11 -0700
- Cc: zsh-users@xxxxxxxxxx
- In-reply-to: <20030729074554.GA1327@os>
- Mailing-list: contact zsh-users-help@xxxxxxxxxx; run by ezmlm
- References: <20030729074554.GA1327@os>
On Tue, Jul 29, 2003 at 09:45:54AM +0200, GoTaR wrote:
> ~: zsh
> ~: slfj zxc ewtg lkjlk
> ^move cursor here and press alt-d
A second (separate) word-delete is needed to get the code to fail, so
I typed ctrl-y, alt-b, alt-d after this.
> ~: slfj zxc lkjlk
> ^move cursor here and press twice alt-y
> ~: slfj zxc lkjlkzsh: segmentation fault zsh
Cause: the first alt-y is considered a yank command, even though it
fails. Thus, the second alt-y can slip by the sanity check at the start
of the yankpop() function, and if "kctbuf" is NULL (as it is if there
was no ctrl-y ever performed), zsh crashes.
The following patch fixes this:
--- Src/Zle/zle_misc.c 27 Feb 2003 11:32:53 -0000 1.8
+++ Src/Zle/zle_misc.c 29 Jul 2003 09:36:12 -0000
@@ -372,8 +372,10 @@
int cc, kctstart = kct;
Cutbuffer buf;
- if (!(lastcmd & ZLE_YANK) || !kring)
+ if (!(lastcmd & ZLE_YANK) || !kring || !kctbuf) {
+ kctbuf = NULL;
return 1;
+ }
do {
/*
* This is supposed to make the yankpop loop
Setting kctbuf to NULL on failure prevents the user from getting a
yanked value out of two consecutive alt-y keystrokes in the case where a
ctrl-y was performed at some point in the past (but not immediately
prior to the alt-y).
I'll commit this to CVS.
..wayne..
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