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compadd and an array parameter
- X-seq: zsh-users 8126
- From: DervishD <zsh@xxxxxxxxxxxx>
- To: Zsh Users <zsh-users@xxxxxxxxxx>
- Subject: compadd and an array parameter
- Date: Tue, 26 Oct 2004 18:59:02 +0200
- Mail-followup-to: Zsh Users <zsh-users@xxxxxxxxxx>
- Mailing-list: contact zsh-users-help@xxxxxxxxxx; run by ezmlm
- Organization: DervishD
    Hi all :)
    I'm playing (again) with the completion code, and I've written
something like this:
    bindkey "^O" completer
    zle -C completer expand-or-complete completer
    function completer () {
        [[ $compstate[context] = "command" ]] && compadd ${commands##*/}
        return 0
    }
    Well, what I want is to complete using the contents of the
'commands' array, but with the path stripped, but I think that the
compadd command above will lead to a very big expansion. Can I tell
compadd something like 'compadd -a commands' and something more to
make it strip the path or the expansion above is the only way?
    Of course, I could examine 'CURRENT', perform a match and include
only that match in the compadd command line, but I'm curious...
    Thanks a lot in advance :)
    Raúl Núñez de Arenas Coronado
-- 
Linux Registered User 88736
http://www.dervishd.net & http://www.pleyades.net/
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