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Re: compadd and an array parameter

X-seq: zsh-users 8135
From: DervishD <zsh@xxxxxxxxxxxx>
To: Zsh Users <zsh-users@xxxxxxxxxx>
Subject: Re: compadd and an array parameter
Date: Wed, 27 Oct 2004 17:06:25 +0200
In-reply-to: <20041026165902.GA6546@DervishD>
Mail-followup-to: Zsh Users <zsh-users@xxxxxxxxxx>
Mailing-list: contact zsh-users-help@xxxxxxxxxx; run by ezmlm
Organization: DervishD
References: <20041026165902.GA6546@DervishD>

    Hi all :)

    My excuses again for self-replying...

 * DervishD <zsh@xxxxxxxxxxxx> dixit:
[...]
>         [[ $compstate[context] = "command" ]] && compadd ${commands##*/}
[...]
>     Well, what I want is to complete using the contents of the
> 'commands' array, but with the path stripped, but I think that the
> compadd command above will lead to a very big expansion. Can I tell
> compadd something like 'compadd -a commands' and something more to
> make it strip the path or the expansion above is the only way?

    Better 'compadd -k commands'. The keys of the 'commands'
associative array are the command names, without path. I don't know
what I was thinking...

    Sorry for the noise. What a day...

    Raúl Núñez de Arenas Coronado

-- 
Linux Registered User 88736
http://www.dervishd.net & http://www.pleyades.net/

References:
- compadd and an array parameter
  - From: DervishD

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