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Re: Can I do without "eval" here?
- X-seq: zsh-users 10015
- From: DervishD <zsh@xxxxxxxxxxxx>
- To: Com MN PG P E B Consultant 3 <mn-pg-p-e-b-consultant-3.com@xxxxxxxxxxx>
- Subject: Re: Can I do without "eval" here?
- Date: Tue, 14 Mar 2006 10:16:19 +0100
- Cc: zsh-users Mailinglist <zsh-users@xxxxxxxxxx>
- In-reply-to: <6F0CB04509C11D46A54232E852E390AC01004881@xxxxxxxxxxxxxxxxxxxxxxxxxx>
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- Organization: DervishD
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Hi Ronald :)
* Com MN PG P E B Consultant 3 <mn-pg-p-e-b-consultant-3.com@xxxxxxxxxxx> dixit:
> What I don't like in this example, is the usage of eval. Although
> it is harmless in this particular case, the filename 'foo', which
> is hardcoded here, comes in as a parameter too in my real
> application, and this means that it undergoes one level of
> evaluation too, which would yield wrong results when it contains,
> say, a $ character.
Try this:
eval whatevercommand \''$file'\'
As for doing the same without eval, it can be done, too, by
setting the sh_word_split option and tweaking, or simply with this:
options=("-x")
(($#)) && options=("-y" "$1")
CMD $options[1] $options[2] foo
If "foo" comes from a parameter, just use that parameter instead
of "foo".
I haven't tested the solution, so it may need some refinement,
but it should do.
Raúl Núñez de Arenas Coronado
--
Linux Registered User 88736 | http://www.dervishd.net
http://www.pleyades.net & http://www.gotesdelluna.net
It's my PC and I'll cry if I want to... RAmen!
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