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Re: Using zsh in gcc compilation
- X-seq: zsh-workers 17697
- From: Peter Stephenson <pws@xxxxxxx>
- To: "David Gómez" <david@xxxxxxxxxxxx>, zsh-workers@xxxxxxxxxx
- Subject: Re: Using zsh in gcc compilation
- Date: Thu, 19 Sep 2002 12:19:27 +0100
- In-reply-to: "Peter Stephenson"'s message of "Thu, 19 Sep 2002 11:07:45 BST." <28819.1032430065@xxxxxxx>
- Mailing-list: contact zsh-workers-help@xxxxxxxxxx; run by ezmlm
Peter Stephenson wrote:
> That's plausible, but I think you'll have to go back and look at what is
> producing that particular part of the xgcc command line, which probably
> means trying to track down the corresponding part of the Makefile. At
> the point you quote, it's already embedded in the command line from
> somewhere earlier.
In particular, look in mklibgcc (generated from mklibgcc.in in the source
directory).
This is using MULTILIBS passed down from the Makefile, so check that
that looks correct.
Just before half way down, this goes into
for ml in $MULTILIBS; do
so check each individual ml is correct.
The $ml then goes into
flags=`echo ${ml} | sed -e 's/^[^;]*;//' -e 's/@/ -/g'`
which is used in
$gcc_compile $flags -E -xassembler-with-cpp -
which is the bit that looks wrong.
--
Peter Stephenson <pws@xxxxxxx> Software Engineer
CSR Ltd., Science Park, Milton Road,
Cambridge, CB4 0WH, UK Tel: +44 (0)1223 692070
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